Solution

The correct answer is 32

EXPLANATION:

The header of the IP datagram given is in hexadecimal format.

Size of the header is 20 to 60 Bytes

Version = 4 bits = (0100)2 (It is IPv4)

Header length = (0101)2 to (1111)2 = 5 bits to 15 bits

Total length = 216 bits

Identification = 216 bits

Fragment Offset = 216 bits

Time to live = 28 bits

Protocol = 28 bits

Header Checksum = 216 bits

SOLUTION:

IP Datagram = 45000054 00030000 2006.......

           20                                 06               

 

The first byte of the IP header contains two fields: the version and the Internet Header Length (IHL). In your case, the first byte is "45" in hexadecimal.

The hop limit (also known as the time-to-live limit in IPv4) is represented by the 8th byte, which in this case is "20" in hexadecimal. This value decrements by one each time the packet passes through a router. When it reaches zero, the packet is discarded.

"20" in hexadecimal translates to 32 in decimal. Therefore, the packet can travel through 32 more routers before it gets discarded.