Solution

The correct answer is 84 bytes

EXPLANATION:

The header of the IP datagram given is in hexadecimal format.

Size of the header is 20 to 60 Bytes

Version = 4 bits = (0100)2 (It is IPv4)

Header length = (0101)2 to (1111)2 = 5 bits to 15 bits

Total length = 216 bits

Identification = 216 bits

Fragment Offset = 216 bits

Time to live = 28 bits

Protocol = 28 bits

Header Checksum = 216 bits

SOLUTION:

IP Datagram = 45000054 00030000 2006.......

         4                             5                          00                           0054

 

The first byte of the IP header contains two fields: the version and the Internet Header Length (IHL). In your case, the first byte is "45" in hexadecimal.

The total length field is the second and third bytes of the IP header, "000054" in this case. These two bytes specify the total length of the whole IP datagram including the header and the data.

"000054" in hexadecimal is 84 in decimal. This value represents the total length of the datagram in bytes.

Therefore, the size of the datagram is 84 bytes.