Solution

The correct answer is -3 db.

Key Points

• Attenuation refers to the reduction in signal power as it travels through a transmission medium.
• When the power of a signal is reduced to half of its initial power, the power ratio (P2/P1) can be calculated as P2 = 1/2 P1.
• Attenuation in decibels (dB) is given by the formula: 10 log₁₀(P2/P1).
• Substituting the values: 10 log₁₀(1/2) = -3 dB.
• Therefore, the power loss in attenuation when the signal power is halved is -3 dB.

Additional Information

• Understanding dB Attenuation:
  • Decibels (dB) are a logarithmic unit used to express ratios, such as power or intensity.
  • Negative dB values represent a decrease in signal power, while positive values indicate amplification.
  • A -3 dB attenuation indicates a 50% reduction in signal power.
• Applications of dB Measurement:
  • Used in telecommunications to measure signal loss or gain.
  • Essential for analyzing the performance of transmission mediums like cables, optical fibers, and wireless networks.
  • Helps in designing systems with optimal signal strength and minimizing losses.
• Importance of Attenuation Calculation:
  • Ensures signal quality during transmission.
  • Helps identify areas of excessive loss and implement corrective measures.
  • Critical for maintaining reliable communication systems.