Solution

The correct answer is None of the above

EXPLANATION:

The number of virtual pages represented by this space can be calculated by dividing total virtual space by the size of an individual page:

4.3 * 10^9 bytes (total virtual space) / 4 * 10^3 bytes (size of individual page) = 1.075 * 10^6 pages

So given that we're dealing with close enough to 1,075,000 pages and each table entry is 5 bytes, the total size of the whole page table would be:

1.075 * 10^6 entries * 5 bytes/entry = 5.375 * 10^6 bytes = 5375 KB or around 5.375 MB.

Mistake Points Given question was some mistake so UGC dropped the question.