Solution

The correct answer is 2

Key Points

• The IP address block is 130.56.0.0/16 and the administrator wants to create 1024 subnets, subnets would have a /26 subnet mask, meaning there are 64 addresses in each subnet.
• Therefore, the first and last addresses of the first subnet would be:
  • The first address (network address) would be the first address of the granted block, that is: 130.56.0.0.
  • Since there are 64 addresses in each subnet, the last address (broadcast address) would be the 63rd increment from the first address, that is: 130.56.0.63.
• So the correct answer would be:
  • First address = 130.56.0.0, Last address = 130.56.0.63

Please note that the first and last addresses in each subnet are typically reserved for network and broadcast addresses respectively, thus they aren't usually assigned to hosts. That means in practice, there would be 62 usable IP addresses in each subnet.