Consider a memory system having address spaced at a distance of m, T = Bank cycle time and n number of banks, then the average data access time per word access in synchronous organisation is
1.t = \(\left\{\begin{array}{l} \rm m \cdot \rm\frac{T}{n} \text { for } \rm m<<n \\ \rm T \text { for } m >> n \end{array}\right.\) ✓ Correct
2.t = \(\left\{\begin{array}{l} \rm T / n \text { for } m << n \\ \rm T \text { for } m >> n \end{array}\right.\)
3.t = \(\left\{\begin{array}{l} \rm m \cdot T \text { for } m << n \\ \rm T \text { for } m >> n \end{array}\right.\)
4.t = \(\left\{\begin{array}{l}\rm m \cdot T \text { for } \rm m << n \\ \rm m/T \text { for } m >> n\end{array}\right.\)