Q88.Marks: +2.0UGC NET Paper 2: Computer Science 2020
📄 Passage
Comprehension: Questions concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
What is the capacity of the disk, in bytes ?
1.25,000 K
2.500,000 K✓ Correct
3.250,000 K
4.50,000 K
Solution
The correct answer is option 2.
Key Points
capacity of the disk = bytes/sector x sector/track x track/surface x surface/disk=512 x 50 x 2000 x 5 x 2